(5+x^2)^1/2=x-3

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Solution for (5+x^2)^1/2=x-3 equation: 


x in (-oo:+oo)

((x^2+5)^1)/2 = x-3 // - x-3

((x^2+5)^1)/2-x+3 = 0

(x^2+5)/2-x+3 = 0

(x^2+5)/2+(2*(-x))/2+(2*3)/2 = 0

x^2+2*(-x)+2*3+5 = 0

x^2-2*x+5+6 = 0

x^2-2*x+11 = 0

x^2-2*x+11 = 0

x^2-2*x+11 = 0

DELTA = (-2)^2-(1*4*11)

DELTA = -40

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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